Question

x² + 17x - 30 (by completing the square)

Answer 1

Answer:

compare the given eqn with ax²+bx+c =0

so, a = 1, b= 17, c = -30

now, dividing eqn with with a,

x²/1 +17x/1 -30/1 = 0/1

=> x² +17x -30 = 0 => x² +17x = 30_____(1)

Now forming [1/2(b/a) ],

[1/2(17/1) ] = 17/2

Adding 17/2 to eqn 1 on both sides,

x²+17x+17/2 = 30+17/2

=> x² +2(17/2) x +17/2 = (60+17)/2

since, a² +b² +2ab = (a+b) ²,

=> (x +17/2) ² = 77/2

=> x+17/2 = √(77/2) => x = √(77/2)-(17/2)

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