x2=17x+60.find the value of x
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x^2 = 17x + 60
x^2 - 17x - 60 = 0
x^2 - 20x + 3x - 60 = 0
x (x - 20) + 3 (x - 20) = 0
(x + 3) (x - 20) = 0
x + 3 = 0 and x - 20 = 0
Ans. the value of x = - 3 and 20
x^2 - 17x - 60 = 0
x^2 - 20x + 3x - 60 = 0
x (x - 20) + 3 (x - 20) = 0
(x + 3) (x - 20) = 0
x + 3 = 0 and x - 20 = 0
Ans. the value of x = - 3 and 20
Answered by
1
Hello,
Here's the answer :-
x^2 = 17x + 60
=> x^2 - 17x -60 = 0
=> x^2 -20x + 3x -60 = 0
=> x(x -20) + 3(x-20) = 0
=> (x+3)(x-20) = 0
When x+3 = 0
=> x = -3
When x-20 = 0
=> x = 20
So, x = -3 or 20
Hope it helped :-)
#Supersonu
#Brainly Benefactor
Here's the answer :-
x^2 = 17x + 60
=> x^2 - 17x -60 = 0
=> x^2 -20x + 3x -60 = 0
=> x(x -20) + 3(x-20) = 0
=> (x+3)(x-20) = 0
When x+3 = 0
=> x = -3
When x-20 = 0
=> x = 20
So, x = -3 or 20
Hope it helped :-)
#Supersonu
#Brainly Benefactor
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