Question

x²-17x+72 =0 slitting the middle term



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Answer 1

Step-by-step explanation:

x²-17x+72 =0

x²-8x-9x+72=0

x(x-8)-9(x-8) = 0

(x-9) (x-8) =0

x= 9,8

Answer 2

Answer:

${x}^{2} - 17x + 72 = 0$

${x}^{2} - (9 + 8)x + 72 = 0$

${x}^{2} - 9x - 8x + 72 = 0$

$x(x - 9) - 8(x - 9) = 0$

$(x - 9)(x - 8) = 0$

$(x - 9) = 0 \: and \: (x - 8) = 0$

$x = 9 \: and \: x = 8$

Ans. (x - 9)(x - 8) and 9 and 8 are the zeros of the polynomial.

Hope it helps.