x²-(√2+1)+√2=0 solve using quadratic formula
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a= 1 , b= -(√2+1) and c= √2
D= b²-4ac =( -2-1 -2√2) - 4×1×√2
= (-3-2√2)-4√2 = -3-2√2-4√2 = -3-6√2
= -3(1+2√2)
x= -b+-√D / 2a
= (√2+1)+- √-3(1+2√2) /2
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