Question

x²-(√2+1)+√2=0 solve using quadratic formula ​

Answer 1

Answer:

a= 1 , b= -(√2+1) and c= √2

D= b²-4ac =( -2-1 -2√2) - 4×1×√2

= (-3-2√2)-4√2 = -3-2√2-4√2 = -3-6√2

= -3(1+2√2)

x= -b+-√D / 2a

= (√2+1)+- √-3(1+2√2) /2