X2-2(1+3k)x+7(3+2k)=0 is 7
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to find the value of k
let x1 and x2 are the roots of this equation. then
(x1+x2)=2(1+3k)
and (x1)(x2)= 7(3+2k–1)
[2(1+3k)^2 – 14(3+2k–1)]
equating this equation with zero you will get the answer
let x1 and x2 are the roots of this equation. then
(x1+x2)=2(1+3k)
and (x1)(x2)= 7(3+2k–1)
[2(1+3k)^2 – 14(3+2k–1)]
equating this equation with zero you will get the answer
ARUNIMAA:
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