Question

x2-(√2+1)x+√2=0 by completing the square

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Samj Rahe ho​

Answer 1

Answer:

(x-1)(x-√2)=0

Step-by-step explanation:

x²-(√2+1)x+√2=0

x²-√2x-x+√2=0

x(x-√2)-1(x-√2)=0

(x-1)(x-√2)=0