x2-(✓2+1)x+✓2=0 find the root quadratic equations
kuldeep1296:
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Step-by-step explanation:
Given quadratic equation is x2-(√2 + 1)x+ √2 = 0 Put x = 1 in the above equation LHS becomes, 1 - (√2 + 1) + √2 = 1 - √2 - 1+ √2 = 0 Hence '1' is the root of the given quadratic equation.
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