x²-(√2+1)x+√2=0
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x = √2 or x = 1 . Pls mark me as brainliest.
Step-by-step explanation:
x² - (√2+1)x + √2 = 0
x² - √2x - x + √2 = 0
x(x - √2) - 1(x - √2) = 0
(x - √2)(x - 1) = 0
x - √2 = 0 or x - 1 = 0
(As product of 0 and any number is 0)
x = √2 or x = 1
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