x²–[√2+1]x+√2 find the zero of the following quadratic polynomial
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that's your answer 1 or root 2
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Step-by-step explanation:
given polynomial = x²-[√2+1]x+√2
As we know, the standard form of quadratic Polynomial is.......
k[x²-(sum of zeros)x+(product of zeros)
here, comparing the given polynomial with the std. form of quad. polynomial
SUM OF ZEROS - √2+1
PRODUCT OF ZEROS - √2
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