Question

x2-2(11x-48) how to factorise this?

Answer 1

Given ,
x^2-2 (11x-48)
= x^2-22x+96
= x^2-16x-6x+96
= x (x-16)-6 (x-16)
= (x-16)(x-6)
hope it helps you

Answer 2

Answer:

We can solve this sum step by step:

Step 1: Expand the equation.

We have the equation: x² - 2 ( 11x - 48 ) = 0

Now we must simplify this by multiplying 2 inside and expanding the equation. We get,

=> x² - 22x + 96 = 0

Step 2: Factorise by splitting the middle term

-22x can be split as -16x and -6x so that on multiplying we get 96.

Hence we get,

=> x² - 16x - 6x + 96 = 0

Step 3: Take common roots and simplify the equation

=> x ( x - 16 ) - 6 ( x - 16 ) = 0

=> ( x - 16 ) ( x - 6 ) = 0

Step 4: Equate the individual products to zero to arrive at the value of x

=> ( x - 16 ) = 0

=> x = 16

=> x - 6 = 0

=> x = 6

Hence the values of x are 6 and 16.