x2 - 2√2x + 2 can u please solve it
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Answered by
1
x2-2√2x+2=0
x2-√2x-√2x+2=0
x(x-√2)-√2(x-√2)=0
(x-√2)(x-√2)=0
x=√2
x2-√2x-√2x+2=0
x(x-√2)-√2(x-√2)=0
(x-√2)(x-√2)=0
x=√2
Answered by
1
x^2 -2√2x + 2 =0
0= x^2- √2x - √2x + 2
0= x(x-√2) - √2(x - √2)
0=(x-√2) (x-√2)
x-√2=0 or x-√2=0
x=√2 or x= √2
hope it will really help u
by Ankita ❤️
0= x^2- √2x - √2x + 2
0= x(x-√2) - √2(x - √2)
0=(x-√2) (x-√2)
x-√2=0 or x-√2=0
x=√2 or x= √2
hope it will really help u
by Ankita ❤️
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mst h
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