Question

x²– 2√3 x - 1 = 0 plzz solve this quadratic equation by discriminating​

Answer 1

Answer: 8

Step-by-step explanation:

Q. x^2 - 2√3x - 1

=(2√3)^2 - 4.1.1.

= 12-4

= 8

= 8>0

So, it's a real root

Thank you...

Answer 2

$\large \bf {x}^{2} - 2 \sqrt{3} x - 1 = 0$

Now,

$\rm = > \: \: \: D = {b}^{2} - 4ac \\ \rm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {( - 2 \sqrt{3} )}^{2} - 4(1)( - 1) \\ \rm\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =12 + 4 = 16$

Then,

$\huge \sf{x = \frac{ - b \pm \sqrt{D} }{2a} } \\ \\ \rm{x = > \frac{ - ( - 2 \sqrt{3}) \pm \sqrt{16} }{2(1)} }\\ \\ \rm{ x = > \frac{2 \sqrt{3} \pm4 }{2} \: \: = \frac{ \cancel2( \sqrt{3} \pm2)}{ \cancel2} }\\ \rm x = > (\red{\sqrt{3 } + 2}) \: \: \: \: \: \: \: or \: \: \: \: \: \: ( \red{\sqrt{3} - 2})$

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