Math, asked by HaqqiAdeeba9055, 11 months ago

x2-2(a+2)x+(a+1)(a+3)=0
solve by quadratic formula

Answers

Answered by rajsudhanshu9431
0

Answer:


Step-by-step explanation:

X2-2(a+2)x+(a+1)(a+3)=0

x2 -(a+1)x-(a+3)x+(a+1)(a+3)

X(x-a-1) -(a+3)(x-a-1)

(x-a-1)(x-a-3)

x= a+1 , x = a+3


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