Question

x²-2(k+1)x+k²=0 then find the value of k​

Answer 1

$\Huge{\red{\underline{\textsf{Answer}}}}$

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The quadratic equation basic formula – ax² + bx + c = 0

a = 1, b = 2(k + 1), c = k²

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For this equation to have equal roots condition is

$\leadsto$b² - 4ac = 0

$\leadsto$[2(k + 1)]² - 4 × 1 × k² = 0

$\leadsto$4(k² + 2k + 1) - 4k² = 0

$\leadsto$4k² + 4(2k + 1) - 4k² = 0

$\leadsto$4(2k + 1) = 0

$\leadsto$2k + 1 = 0

$\leadsto$2k = -1

$\leadsto$k = -1/2

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❤️$\mathcal{BE \: BRAINLY}$❤️

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Answer 2

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$\huge\tt{GIVEN:}$

• an equation, x²-2(k+1)x+k²=0

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$\huge\tt{TO~FIND:}$

• THE VALUE OF K

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$\huge\tt{SOLUTION:}$

↪b² - 4ac = 0

↪[2(k + 1)]² - 4 × 1 × k² = 0

↪4(k² + 2k + 1) - 4k² = 0

↪4k² + 4(2k + 1) - 4k² = 0

↪4(2k + 1) = 0

↪2k + 1 = 0

↪2k = -1

↪k = -1/2

$\rule{200}2$