Question

x² + 20x + 64 ÷ x+4

plz​

Answer 1

Step-by-step explanation:

$( {x}^{2} + 20x + 64) \div (x + 4)$

$= \frac{ {x}^{2} + 16x + 4x + 64}{x + 4}$

$= \frac{x(x + 16) + 4(x + 16)}{x + 4}$

$= \frac{(x + 4)(x + 16)}{(x + 4)}$

$= x + 16$

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Answer 2

Answer:

» (x² + 20x + 64) ÷ (x + 4)

= [x² + 20x + 64] / (x + 4)

= [x² + 4x + 16x + 64] / (x + 4)

= [(x + 4) (x + 16)] / (x + 4)

= x + 16