Question

X²-2²⁰²⁰x+|x-2²⁰¹⁹|+2 (2⁴⁰³⁷-1) =0?

Answer 1

Answer:

(x-1)(x+2) = 2²⁰¹⁹(2x-1)

Step-by-step explanation:

X²-2²⁰²⁰x+|x-2²⁰¹⁹|+2 (2⁴⁰³⁷-1) =0?

Let 2²⁰¹⁹ = p

x² - 2px + x - p + 2p - 2 = 0

x² - 2px + x - p - 2 = 0

x² + x - 2 = 2px - p

(x-1)(x+2) = p(2x-1)

(x-1)(x+2) = 2²⁰¹⁹(2x-1)

I'm stuck