Question

x2 - 22x + 10 = 0 has a root of a and B. find a-B​

Answer 1

Step-by-step explanation:

Factoring x2-22x-10

The first term is, x2 its coefficient is 1 .

The middle term is, -22x its coefficient is -22 .

The last term, "the constant", is -10

Step-1 : Multiply the coefficient of the first term by the constant 1 • -10 = -10

Step-2 : Find two factors of -10 whose sum equals the coefficient of the middle term, which is -22 .

-10 + 1 = -9

-5 + 2 = -3

-2 + 5 = 3

-1 + 10 = 9

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Answer 2

x^2-22x+10=0

we are given the following

x^2-22x=10

completing the square,we have

x^2-22x+121=10+121

(x-11)^2=131

x-11=+-✓131

X=11++-✓131