Question

x2-24x+100=0 find the roots​

Answer 1

Answer:

D = b^2 - 4ac

D = b^2 - 4ac D = 576 -4 *1 *100

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14 therefore it's two roots with

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14 therefore it's two roots with-b ±rootD

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14 therefore it's two roots with-b ±rootD therefore first root will be : root D + (-b)

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14 therefore it's two roots with-b ±rootD therefore first root will be : root D + (-b) 24 + 14

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14 therefore it's two roots with-b ±rootD therefore first root will be : root D + (-b) 24 + 1438

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14 therefore it's two roots with-b ±rootD therefore first root will be : root D + (-b) 24 + 1438 second root : 24 - 14

D = b^2 - 4ac D = 576 -4 *1 *100D = ,176 or, root D=14 therefore it's two roots with-b ±rootD therefore first root will be : root D + (-b) 24 + 1438 second root : 24 - 14 10

Step-by-step explanation:

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