x²–25x–156=0 completing the square
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Answers
Answer:
Simplifying
x2 + -25x + 156 = 0
Reorder the terms:
156 + -25x + x2 = 0
Solving
156 + -25x + x2 = 0
Solving for variable 'x'.
Factor a trinomial.
(12 + -1x)(13 + -1x) = 0
Subproblem 1
Set the factor '(12 + -1x)' equal to zero and attempt to solve:
Simplifying
12 + -1x = 0
Solving
12 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-12' to each side of the equation.
12 + -12 + -1x = 0 + -12
Combine like terms: 12 + -12 = 0
0 + -1x = 0 + -12
-1x = 0 + -12
Combine like terms: 0 + -12 = -12
-1x = -12
Divide each side by '-1'.
x = 12
Simplifying
x = 12
Subproblem 2
Set the factor '(13 + -1x)' equal to zero and attempt to solve:
Simplifying
13 + -1x = 0
Solving
13 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-13' to each side of the equation.
13 + -13 + -1x = 0 + -13
Combine like terms: 13 + -13 = 0
0 + -1x = 0 + -13
-1x = 0 + -13
Combine like terms: 0 + -13 = -13
-1x = -13
Divide each side by '-1'.
x = 13
Simplifying
x = 13
Solution
x = {12, 13}
Answer:
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