x2-28x+187=0.find x value
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x²-17x-11x+187=0
=> x(x-17)-11(x-17)=0
=> (x-17)(x-11)=0
=> x-17=0,x-11=0
=> x =17 , x=11
here is ur answer
=> x(x-17)-11(x-17)=0
=> (x-17)(x-11)=0
=> x-17=0,x-11=0
=> x =17 , x=11
here is ur answer
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