Question

x²-2ax +(a+b) (a-b)​

Answer 1

Answer:

x² - 2ax/(a+b) + (a-b)/(a+b) = 0

[x - a/(a+b)]² + (a-b)/(a+b) - a²/(a+b)² = 0

[x - a/(a+b)]² = b²/(a+b)²

x - a/(a+b) = ±b/(a+b)

Step-by-step explanation:

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Answer 2

it's a factorization

x²-2ax+(a+b)(a-b)

=x²-(a+b)x-(a-b)x+(a+b)(a-b)

=x(x-a-b)-(a-b)(x-a-b)

=(x-a+b)(x-a-b)

it is called special type middle term factorization

in this factorization process we find the coefficient and then multiply this with the second and third term and after it again two terms are sat In correct operation (+,-,×,÷)