x2-2ax+(a2-b)=0 using factorization method
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x^2-2ax+a^2-b=0
rearranging the terms,
x^2+a^2-2ax-b=0
(x-a)^2-b=0
(x-a)^2=b
x-a=root b
rearranging the terms,
x^2+a^2-2ax-b=0
(x-a)^2-b=0
(x-a)^2=b
x-a=root b
ochigboemmanuel32:
Not really i need the roots
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