Question

x²+2ax+(a²-b²)=0

factorize the equation pls
I will mark you as brainliest answer ​

Answer 1

Answer:

Hii !

Step-by-step explanation:

x² - 2ax + (a² - b²) = 0

(x² - 2ax + a²) - (b²) = 0

(x)² - 2a×x + (a)² - b²

(x - a)² - (b)² = 0

[(a)² - 2ab + (b)² = (a - b)²]

(x - a - b) (x - a + b) = 0

[ a² - b² = (a - b)(a + b)]

x - a - b = 0 or x - a + b = 0

x = a + b or x = a - b

Hence, the value of x is (a +b) or (a-b)

Hope it will be helpful !

Answer 2

Answer:

$x = -(a+b),-(a-b)$

Step-by-step explanation:

Given,

$x^{2}+ 2ax + (a^{2}- b^{2}) = 0$

or, $x^{2}+ [(a+b )(a-b)]x+(a-b)(a+b)$

or, $x(x+a+b)+(a-b)(x+a+b)=0$

or, $(x+a+b)(x+(a-b))=0$

or, $x = -(a+b),-(a-b)$

hence the value of x is both -(a + b) and -(a - b)