Question

x2 - (2b-1)x +(b2 - b-20) =0​

Answer 1

Answer:

x = b + 4 or x = b - 5.

Step-by-step explanation:

x2 - (2b - 1) x + (b2-b-20) = 0

When we Compare the above equation with

Ax2 + Bx + C = 0, We get..

A = 1B = -(2b - 1)C = b2-b-20

Now, D = B2 - 4AC

= (2b - 1)2 - 4(b2-b-20)

= 4 b2 +1-4b - 4b2 + 4b + 80

= 81 > 0

So, the above equation has 2 real and distinct r oots given by,

x = - B + D√2A or x = - B - D√2A

⇒ x = 2b - 1 + 92 or x = 2b - 1 - 92

⇒ x = b + 4 or x = b - 5.

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