Math, asked by Babupatel4226, 9 months ago

X2+2k(x-2)+5=0 find values (not value) of k

Answers

Answered by NabothMalaya1
0

Answer:

x=-5-4k/2+2k

Step-by-step explanation:

firstly open the brackets which will be

  1. x2+2kx-4k+5=0
  2. arrange the equation;
  3. x2+2kx=-5-4k
  4. factorise it so that u get x
  5. x(2+2k)=-5-4k
  6. divide both sides by 2+2k to get x
  7. x(2+2k)/2+2k=-5-4k/2+2k
  8. so the 2+2k/2+2k will get canceled and you will remain with x
  9. thats why the answer is x=-5-4k/2+2k

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