Question

x2 - 2kx + 7k - 12 = 0​

Answer 1

Answer:

x

2

−2kx+7k−12=0

For equal & real roots, D≡0

D≡+4k

2

−(7k−12)(1)(4)

0≡+4K

2

−28k+48

0=+K

2

−7k+12

K

2

−4k−3k+12

0=(k−4)(k−3)

⇒k=4,3