Question

x2-2kx+7k-12=0 has equal roots find the value of k

Answer 1

hy
For equal roots

b sq =4 ac

(-2k)sq = 4 .1.(7k -12)

4 k sq = 4(7k-12)

k sq = 7k -12

k sq - 7k +12=0

k sq -4k -3k +12=0

k (k -4)-3(k-4)=0

(k-4)(k-3)=0

ie k=3,4 ans

hope it helps

Answer 2

Answer:

pls mark as brainliest friend

Step-by-step explanation:

X2-2kx+7k-12=0

A = 1 , b = -2k , c = 7k-12

d = b^2 - 4ac

= 4k^2 - 4 × 1 × 7k-12

= 4k^2 - 28k + 48 = 0

= k^2 - 7k + 12 = 0

= (k-4) (k-3) = 0

= k = 4 , k = 3