Question

x2+2root2x-6 find zeros

Answer 1

${x}^{2} + 2 \sqrt{2} x - 6 = 0 \\ {x}^{2} + 3 \sqrt{2}x - \sqrt{2}x - 6 = 0 \\ x(x + 3 \sqrt{2} ) - \sqrt{2} (x + 3 \sqrt{2} ) \\ (x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0 \\ \\ x = \sqrt{2} or \: x = - 3 \sqrt{2}$
hope it will help you!!

Answer 2

It is a nice question I am trying my best