Question

x²-2x+1=0 find x⁹⁹+1/x⁹⁹​

Answer 1

Answer:

${(x - 1)}^{2} = 0 \\ x = 1 \\ now {x}^{99} + {(1 \div x)}^{99} = {1}^{99} + {1}^{99} = 1 + 1 = 2$

Answer 2

Step-by-step explanation:

x^2-2x+1=0

x^2-x-x+1=0

x(x-1)-1(x-1)=0

(x-1)(x-1)=0

x=1

x^99+1/x^99

1^99+1/1^99

1+1/1=2/1

2