Question

x²+2x+1=0,slove as quadratic equation​

Answer 1

Answer:

(x−1)2=0

Explanation:

x2−2x+1=0

Let's start by subtracting 1 from both sides so that the x terms are isolated:

x2−2x=−1

Now, let's compute (b2)2 and add it to both sides of the equation:

(b2)2=(−22)2=1

x2−2x+1=−1+1

Let's factorize the left hand side and simplify:

(x−1)(x−1)=0

(x−1)2=0

Step-by-step explanation:

Answer 2

${x}^{2} + 2x + 1 = 0 \\ {x}^{2} + x + x + 1 = 0 \\ x(x + 1) + 1(x + 1) = 0 \\ (x + 1)(x + 1) = 0 \\ {(x + 1)}^{2} = 0 \\ x + 1 = \sqrt{0} \\ x = - 1$