Question

x²+(2x-1)²=(2x+1)²
x²+4x²-4x+1=4x²+4x+1
x²-8x=0
How?​

Answer 1

Step-by-step explanation:

Put x = 8

you will find your answer

Answer 2

Step-by-step explanation:

rechecking:

x²-8x = 0

take x common

x(x-8) = 0

x goes right side then it divides 0/x then it is 0

x-8=0

x=8

substitute x as 8 in the equation

if it results 0

then it is proved

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