Question

x²-2x-1 ke factor jLdi batana​

Answer 1

Step-by-step explanation:

method 1

x²-2x-1=0

x=(-b±√b²-4ac)/2a

a=1 b= -2 c= -1

x= {2±[√4-(4)(1)(-1)]}/2(1)

x= 2± √8 / 2

x= 2±(√4×2)/2

x= 1±√2