Question

x²+2x-15 factories plz​

Answer 1

Answer: The solution is (x+ 3)(x- 5)

x²+2x-15=(x+ 3)(x- 5)

Step-by-step explanation:1) Make the skelton(x  )(x  )=0

2) Add the signs

(i)if all the terms are positive:(x+  )(x+  )=0

(ii)if the center term is negative:(x-  )(x-  )=0

(iii)if the last term is negative(x+  )(x- )=0

(iv)if both the middle term and last term is negative(x+  )(x- )=0

3)Find the factors for last term should equal the middle term

4)Check work with FOIL method

As mentioned above step:

1)Make a skelton

(x   )(x   )=0

2)if the last term is negative,

(x+  )(x- )=0

3)Now,Find the factors for last term should equal the middle term

-15 factors are=1 x 15  and 3 x 5

So,(x+ 3)(x- 5)=0

(x+ 3)(x- 5) = X^2-5X+3X-15

=X^2-2X-15

4)Now, check using FOIL Method,

(x+ 3)(x- 5)

X+3=0           X+5=0                    

X=-3             X=-5

By factorizing, we get the solution,

(x+ 3)(x- 5)