Question

(x²-2x)²-3(x²-2x)-y(x²-2x)+3y
Factorize it.
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Answer 1

$\rm{\left(x^2+2x\right)^2-3\left(x^2+2x\right)-y\left(x^2+2x\right)+3y}$

$\rm{=\left(x^2+2x\right)\left(x-1\right)\left(x+3\right)-y\left(x-1\right)\left(x+3\right)}$

$\rm{=\left(-1+x\right)\left(3+x\right)\left(x^2+2x\right)-\left(-1+x\right)\left(3+x\right)y}$

$\rm{=\left(-1+x\right)\left(3+x\right)\left(x^2+2x-y\right)}$