x2+2x-24 find the zero of the following quadratic
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Answer:
4, -6
Step-by-step explanation:
p(x)=x²+2x-24
=x²-4x+6x-24
=x(x-4)+6(x-4)
=(x+6)(x-4)
For p(x)=0
x+6=0 x-4=0
x= -6 x=4
So, zeroes are 4, -6
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