Question

(x²+2x+3)(x²-3)(x-3)​

Answer 1

Answer:

Given f(x)=x²-2x-3

Substitute x = 3 in f(x), we get

The value of f(x)=

f(3)= 3²-2(3)-3

= 9–6–3

= 0

Therefore,

If x=3 ,the value of f(x)=0.