(x²+2x+3)(x²-3)(x-3)
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Answer:
Given f(x)=x²-2x-3
Substitute x = 3 in f(x), we get
The value of f(x)=
f(3)= 3²-2(3)-3
= 9–6–3
= 0
Therefore,
If x=3 ,the value of f(x)=0.
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