Question

X² + 2x - 5 = 0 find roots

Answer 1

${x}^{2} + 2x - 5 = 0 \\ here \: d = {b}^{2} - 4ac \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = {2}^{2} - (4.1. - 5) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 4 + 20 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 24$

$so \sqrt{24} = 2 \sqrt{6}$

so,

$\frac{ - b + - \sqrt{d} }{2a} \\ = \frac{ - 2 + - 2 \sqrt{6} }{2.1} \\ = \frac{ 2( - 1 + - \ \sqrt{6}) }{2} \\ = - 1 + \sqrt{6} \: \: and \: \: - 1 - \sqrt{6} (ans)$

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