Question

x²+2x+5=0 solve quadratic equation by factorization​

Answer 1

answer in attachment

hope it helpsssssss

Answer 2

given,

x²+2x+5=0

$x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:5}}{2\cdot \:1}\\x_{1,\:2}=\frac{-2\pm \:4i}{2\cdot \:1}\\x_1=\frac{-2+4i}{2\cdot \:1},\:\\x_2=\frac{-2-4i}{2\cdot \:1}\\=\frac{-2+4i}{2\cdot \:1}\\\mathrm{Multiply\:the\:numbers:}\:2\cdot \:1=2\\=-2+4i\\=-2\cdot \:1+2\cdot \:2i\\=2\left(-1+2i\right)\\\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1\\=-1+2i\\=\frac{-2-4i}{2\cdot \:1}\\\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1\\=-\left(1+2i\right)\\=-1-2i\\x=-1+2i,\:\\x=-1-2i$