Question

(x²+2x -5) + (3x²-8x-5)=?
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Answer 1

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(x²+2x-5)+(3x²-8x-5)=?

$\: \\ \implies \bf{( {x}^{2} + 2x - 5) + (3 {x}^{2} - 8x - 5)}$

$\: \: \\ \implies \displaystyle \bf{( {x}^{2} + 2x - 5 + {3x}^{2} - 8x - 5) = 0}$

$\: \implies \displaystyle \bf{(4 {x}^{2} - 6x - 10) = 0}$

$\: \: \bigstar \underline{ \boxed{ \rm{by \: formula}}}$

$\: \implies \bf{2 {x}^{2} - 3x - 5} = 0$

$\: \implies \displaystyle \bf{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }$

$\: \implies \displaystyle \bf{x = \frac{3 \pm \sqrt{ {(3)}^{2} - 4(2)(5) } }{2 \times 2} }$

$\: \implies \displaystyle \bf{x = \frac{3 \pm \sqrt{9 - 40} }{4} }$

$\: \: \implies \displaystyle \bf{x = \frac{3 \pm \sqrt{-31} }{4} }$

$\: \bigstar \boxed{ \bf{x = \frac{3 + \sqrt{31} }{4} \: and \: x = \frac{3 - \sqrt{31} }{4} \: is \: the \: answer}}$

Answer 2

hope the upper picture helps you

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