Question

x²-2x-8=0
$x2 - 2x - 8 = 0$

Answer 1

Hey !!


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See !!!


x2 - 2x - 8 = 0

x2 -4x + 2x - 8 = 0

x ( x - 4 ) + 2 ( x - 4 ) = 0

(x + 2 ) ( x - 4 ) = 0

Answer 2

ANSWER
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${x}^{2} - 2x - 8 = 0$
BREAKING DOWN THE SECOND TERM
${x}^{2} - 4x + 2x - 8 = 0$
TAKING OUT COMMON
$x(x - 4) + \: 2(x - 4) = 0$
$(x + 2)(x - 4) = 0$
SINCE TWO TERMS ARE MULTIPLIED,
ONE OF THEM SHOULD BE ZERO TO GET PRODUCT ZERO

THEREFORE,

$x \: = \: + 4 \: \: or \: - 2$
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HOPE IT HELPS :):):):):)