x2 -2x-8 find he zero
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Answered by
2
x^2-2x-8=0
x^2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
so x-4 =0 or x+2 =0
then x=4 or x= -2
so the value of x is 4 or -2
hope you get your ans
plz mar me as brainliest
x^2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
so x-4 =0 or x+2 =0
then x=4 or x= -2
so the value of x is 4 or -2
hope you get your ans
plz mar me as brainliest
Answered by
6
Hii friend,
X²-2X-8
X²-4X +2X -8
X(X-4) +2(X-4)
(X-4) (X+2)
X -4 = 0. OR X +2 = 0
X = 4. OR X = -2
HOPE IT WILL HELP YOU...... :-)
X²-2X-8
X²-4X +2X -8
X(X-4) +2(X-4)
(X-4) (X+2)
X -4 = 0. OR X +2 = 0
X = 4. OR X = -2
HOPE IT WILL HELP YOU...... :-)
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