Question

x²-2x-8 find the zeros Give Explaination​

Answer 1

x²-2x-8

= x^2 - (4 - 2)x - 8

= x^2 - 4x + 2x - 8

= x(x - 4) + 2(x - 4)

= (x - 4) (x + 2)

Answer 2

Answer:

Zeroes of the equation are x= 4 & -2

Step-by-step explanation:

$x^{2} -2x-8 =0$

$x^{2} -4x+2x -8=0$

$x(x-4)+2(x-4)=0$

$(x-4)(x+2)=0$

$x=4,-2$

Hope it helps!