Question

x2-2x-8 find the zeros of quadratic polynomial and verify relationship between zeros and co-efficient ​

Answer 1

Answer:

In short

x = 4 and -2

sum of zeros = - coeff of x / coeff of x2

product of zeros =  

constant term / coeff of x2

Step-by-step explanation:

Answer 2

HEYA USER ❤️

let

x²-2x-8=0

By splitting middle term,

x²-4x+2x-8=0

x(x-4)+2(x-4)=0

(x+2)(x-4)=0

(x+2)=0. (x-4)=0

x=-2. x=4