Question

x2-2x-8 find zero and veryfy relationship between zeros and ther coefficient ​

Answer 1

Answer:

Given equation:  x2−2x−8

Zero of a equation means a value of the variable that when substituted in the equation, gives the value of the equation as 0.

Therefore, equating our given equation with 0, we get

x2−2x−8=0

Now, using the quadratic formula that is

x= -b ± b² - 4ac      [  square root lagana hain ]

      2a

Where,  a=1, b=−2, c=−8

x= -[ -2 ] ± [-2]² - 4[1][-8]

           2[1]

x= 2± 4 + 32      

          2      

x= 2 ±    [$\sqrt{36 }$]        [  square root lagana hain ]

         2

x= 2+ 6 and second value=  x= 2-6

       2                                              2

x= 8/2 = 4   and second value= -4/2= - 2

Hence, the two zeros of the quadratic equation x2−2x−8 are 4 and -2

α=4  

β=−2

Sum of zeros  (α+β)=−b\a

                      4+(−2)= −(−2)/1

                       4−2=2\1

                            2=2

Hence, LHS=RHS.

Therefore, the first relation is verified.

⇒Product of zeros:

(αβ) = ca

(4)(−2)= −8/1

       −8= −8

Hence, LHS=RHS.

Therefore, the second relationship is also verified.

Step-by-step explanation: