x2-2x-8
Find Zeroes palynomial
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x2-2x-8=0
x2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x+2)(x-4)=0
x= -2 or x=4
x2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x+2)(x-4)=0
x= -2 or x=4
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