Question

x2 - 2x -8 find zeroes snd verify relationships ​

Answer 1

Answer:

-2 & 4

Step-by-step explanation:

${x}^{2} - 2x - 8 = 0 \\ = > {x}^{2} - 4x + 2x - 8 = 0 \\ = > x(x - 4) + 2(x - 4) = 0 \\ = > (x + 2)(x - 4) = 0 \\ = > x = - 2 \: or \: 4$

Answer 2

Answer:

x= -2,4

Step-by-step explanation:

x²-2x-8=0

x²-(4x-2x)-8=0

x²-4x+2x-8=0

x(x-4)+2(x-4)=0

(x+2)(x-4)=0

x= -2 x=4

VERIFICATION,

putting values of x= -2,4 in (x²-2x-8=0)

(a.)(-2)²-2(-2)-8=0

4+4-8=0

8-8=0

0=0

(b.)(4)²-2(4)-8=0

16-8-8=0

16-16=0

0=0