X2-2x-8 polynomial solution
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HERE IS YOUR ANSWER.
☆Factorization of the following polynomial:-
--》 x^2 - 2x - 8
( ax^2 + bx + c , a # 0 )
a = 1
b = - 2
c = - 8
a × c = 1 × 8 = 8 = - 4 × 2
b = -2 = - 4 + 2
x^2 - 2x - 8
x^2 - (4 + 2 ) x - 8
x^2 - 4x - 2x - 8
x ( x - 4 ) -2 ( x - 4 )
( x - 2 ) ( x - 4 )
Hence , Factorised the given polynomial by splitting - mid term .
THANKS
HOPE ITS HELPFUL
PLZ MARK IT AS BRAINLIEST
☆☆☆☆☆☆☆☆☆☆☆☆☆☆
HERE IS YOUR ANSWER.
☆Factorization of the following polynomial:-
--》 x^2 - 2x - 8
( ax^2 + bx + c , a # 0 )
a = 1
b = - 2
c = - 8
a × c = 1 × 8 = 8 = - 4 × 2
b = -2 = - 4 + 2
x^2 - 2x - 8
x^2 - (4 + 2 ) x - 8
x^2 - 4x - 2x - 8
x ( x - 4 ) -2 ( x - 4 )
( x - 2 ) ( x - 4 )
Hence , Factorised the given polynomial by splitting - mid term .
THANKS
HOPE ITS HELPFUL
PLZ MARK IT AS BRAINLIEST
☆☆☆☆☆☆☆☆☆☆☆☆☆☆
Mark it as Brainliest plz ...
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