Question

x²– 2x – 8 द्विघातीय बहुपद के शून्यक ज्ञात कीजिये:-

Answer 1

Step-by-step explanation:

${x}^{2} - 2x - 8 \\ = {x}^{2} - 4x + 2x - 8 \\ = x \times (x - 4) + 2 \times (x - 4) \\ = (x - 4) \times (x + 2) \\ x = 4 \: \: \: or \: x = - 2$