Question

x2+2x-8 zeroes of polynomial ​

Answer 1

Answer:

x=4,-2

Step-by-step explanation:

$x^{2} +2x-8\\x^{2} +2x-4x-8\\(x^{2} +2x) -(4x-8)\\x(x+2) -4(x+2)\\(x-4) (x+2)\\x-4=0, x+2=0\\x=4,x=-2$

Answer 2

Answer:

2 & – 4

Step-by-step explanation:

x² + 2x –8

x² + 4x –2x –8

x (x+4) – 2(x+4)

(x–2)(x+4)

x = 2 & – 4