Question

(x²+2x)(x²-2x-3)-4=0​

Answer 1

Step-by-step explanation:

x2-2x-3/4=0

We add all the numbers together, and all the variables

x^2-2x-3/4=0

We multiply all the terms by the denominator

x^2*4-2x*4-3=0

Wy multiply elements

4x^2-8x-3=0

a = 4; b = -8; c = -3;

Δ = b2-4ac

Δ = -82-4·4·(-3)

Δ = 112

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

The end solution:

Δ−−√=112−−−√=16∗7−−−−−√=16−−√∗7√=47√

x1=−b−Δ√2a=−(−8)−47√2∗4=8−47√8

x2=−b+Δ√2a=−(−8)+47√2∗4=8+47√8

Answer 2

(x^2+2x)(4x^2+8x+12) = 0

x^2(-4x^2+8x+12) + 2x(-4x^2+8x+12) = 0

-4x^4+8x^3+12x^2-8x^3+16x^2+24x=0

-4x^4+28x^2+24x=0

(-x^3+7x+6)=0